Stop Paying for Each Search Engine Separately

The Problem

Most teams running multi-platform search end up with a separate vendor for each engine. One subscription covers Google SERP, another handles Amazon product data, a third provides YouTube metadata, and a fourth delivers Walmart listings. Each vendor has its own authentication model, its own rate-limit policy, its own billing cycle, and its own schema quirks. The result is four invoices, four sets of API keys in your secrets manager, four support channels, and four different retry strategies in your codebase. The total bill is the sum of four entry plans even if you only run a few hundred queries per platform per day. Vendor sprawl is expensive, fragile, and a compliance headache that grows linearly with every platform you add.

The Scavio Solution

Scavio covers Google, Amazon, YouTube, Walmart, and Reddit behind a single API key and a single billing plan. You pay once, you authenticate once, and you get a normalized response shape regardless of which platform you query. There are no per-platform add-on fees, no separate tier gates, and no surprise invoice from a vendor you forgot you signed up for. The free tier includes 500 credits that work across all platforms, and paid plans scale from nine dollars a month to five hundred. One key, one dashboard, one bill, and one vendor to evaluate at renewal time.

Who It Is For

Engineering leads and finance teams tired of managing multiple search API subscriptions. If your current vendor stack includes SerpApi plus Rainforest plus a YouTube scraper plus a Walmart integration, this collapses all of it into one account.

Key Benefits

• One API key covers five platforms with no add-on fees
• Single invoice replaces four separate vendor contracts
• Free tier of 500 credits works across all platforms
• No per-platform tier gates or premium multipliers
• One security review instead of four vendor assessments

Python Example

import requests

API_KEY = "your_scavio_api_key"
URL = "https://api.scavio.dev/api/v1/search"

def search_all(query: str):
    platforms = ["google", "amazon", "youtube", "walmart"]
    results = {}
    for platform in platforms:
        r = requests.post(
            URL,
            headers={"x-api-key": API_KEY},
            json={"platform": platform, "query": query},
            timeout=10,
        )
        data = r.json()
        results[platform] = len(data.get("organic", []))
    return results

coverage = search_all("noise cancelling headphones")
for platform, count in coverage.items():
    print(f"{platform}: {count} results")

JavaScript Example

const API_KEY = "your_scavio_api_key";
const URL = "https://api.scavio.dev/api/v1/search";

async function searchAll(query) {
  const platforms = ["google", "amazon", "youtube", "walmart"];
  const results = {};
  for (const platform of platforms) {
    const r = await fetch(URL, {
      method: "POST",
      headers: {
        "x-api-key": API_KEY,
        "content-type": "application/json",
      },
      body: JSON.stringify({ platform, query }),
    });
    const data = await r.json();
    results[platform] = (data.organic ?? []).length;
  }
  return results;
}

const coverage = await searchAll("noise cancelling headphones");
for (const [platform, count] of Object.entries(coverage)) {
  console.log(`${platform}: ${count} results`);
}

Platforms Used