The Problem
SEO professionals pay $129-$249/month for tools like Ahrefs or Semrush but only run a handful of rank checks per week. The per-query cost at low usage is $1-5 per search, yet they are locked into monthly subscriptions regardless of volume.
The Scavio Solution
Replace subscription-based rank checks with Scavio API calls at $0.005 per credit. For a team running 200 rank checks per month, the cost drops from $129/mo (Ahrefs Lite) to ~$1/mo on Scavio. Use the Google endpoint to pull organic rankings, then parse position data programmatically.
Before
Paying $129-$249/mo for Ahrefs or Semrush. Using less than 5% of the included quota. Effective cost per query is $1-5.
After
Pay-as-you-go at $0.005/credit. 200 checks/month costs $1. Same SERP data, no subscription lock-in. Free tier covers light users entirely (500 free/mo).
Who It Is For
Freelance SEOs, small agency owners, indie hackers, and solo marketers who need rank tracking without enterprise subscriptions.
Key Benefits
- $0.005/credit vs $129+/mo subscription
- 500 free credits cover light monthly usage
- No annual contract or lock-in
- Same organic ranking data available via API
- Programmatic access enables custom dashboards
Python Example
import requests, os
H = {'x-api-key': os.environ['SCAVIO_API_KEY']}
def check_rank(keyword: str, target_domain: str) -> int | None:
resp = requests.post('https://api.scavio.dev/api/v1/search',
headers=H, json={'platform': 'google', 'query': keyword}, timeout=10)
for r in resp.json().get('organic', []):
if target_domain in r.get('link', ''):
return r['position']
return None
for kw in ['best crm software', 'project management tool']:
pos = check_rank(kw, 'mysite.com')
print(f'{kw}: position {pos}')JavaScript Example
async function checkRank(keyword, targetDomain) {
const resp = await fetch('https://api.scavio.dev/api/v1/search', {
method: 'POST',
headers: { 'x-api-key': process.env.SCAVIO_API_KEY, 'Content-Type': 'application/json' },
body: JSON.stringify({ platform: 'google', query: keyword })
});
const data = await resp.json();
const match = (data.organic || []).find(r => r.link?.includes(targetDomain));
return match ? match.position : null;
}Platforms Used
Web search with knowledge graph, PAA, and AI overviews